Nuprl Definition : fpf-val 11,40

z != f(x P(a;z) == (x  dom(f))  P(x;f(x)) 
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clarification:

fpf-val(eqfxa,z.P(a;z)) == (fpf-dom(eqxf))  P(x;feq(x)) 
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Definitionsf(x), x  dom(f), b, P  Q
FDL editor aliasesfpf-val

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